Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more if 2^mn/2^nm=16 and a=2^1/10,then find a^2mnp/(a^m2n2p)^1 this solution is given wrong in your RD sharma textbook solutions Maths Exponents of Real NumbersIf 2 m n 2 nm = 16, 3 p 3 n = 81 and a = 2 1 / 10, then a 2 m np (a m2 n 2 p)1 = (a) 2 (b) 1 4 (c) 9 (d) 1 8 Answer Given , 3 p 3 n = 81 and To find Find By using rational components We get By equating rational exponents we get Now, = a 2 m np a m2 n 2 p we get = a 2 m np m2 n 2 p = a 3 mn p Now
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If 2^m+n/2^n-m=16
If 2^m+n/2^n-m=16-Click here👆to get an answer to your question ️ \"If \\( \\frac { 2 ^ { m n } } { 2 ^ { n m } } = 16 , \\frac { 3 ^ { p } } { 3 ^ { n } } = 81 \\) and \\( aThe sum of two numbers is 7 If one number is subtracted from the other, the
If 2 M N 2 N M 16 Amp A 2 1 10 Then Find The Value Of A 3m Brainly In
If 2^mn/2^nm=16 and a=2^1/10 then find a^2mnp/ (a^m2np)^1 Ayaan, one year ago Grade9 × FOLLOW QUESTION We will notify on your mail & mobile when someone answers this question Enter email id Enter mobile number 91 United States 1If 2 M N 2 N − M = 16 , 3 P 3 N = 81 and a = 2 1 / 10 ,Than a 2 M N − P ( a M − 2 N 2 P ) − 1 =RD Sharma solutions for Mathematics for Class 9 chapter 2 (Exponents of Real Numbers) include all questions with solution and detail explanation This will clear students doubts about any question and improve application skills while preparing for board exams The detailed, stepbystep solutions will help you understand the concepts better and clear your confusions, if any
Related Questions The sum of three consecutive numbers is 210 What is the largest of these numbers? 2`1/4``3`2 Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams Stepbystep explanation If 2^mn / 2^nm = 16 & a = 2^1/10 then a^2mnp / (am2n2p)^1 => m = 2 jd3sp4o0y and 197 more users found
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